the only approach for system of ineq is 2 try pt.s

identity means LHS---RHS for all possibe unknowns

(cosx)^2=1
how many roots?

smiliar 3D should also prop with all their size

when operating reflexing,
bear in mind the side length

from x^0.5 to x
it seems take sp or log are the only ways

(a-b)x^2 + (b-c)x + (a-b)
deta=0

Rhombus

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parall's dignal not always bisect the angles

some qu with time should think at initily&nbsp;

Trasformation and Symmetry

2D
&nbsp;&nbsp;Transformation
&nbsp;&nbsp; &nbsp;Reflection
&nbsp;&nbsp; &nbsp;Rotation
&nbsp;&nbsp; &nbsp;Translation
&nbsp;&nbsp; &nbsp;Dilation &nbsp; (scale factor)
&nbsp;&nbsp;Symmerty
&nbsp;&nbsp; &nbsp;Reflectional symmetry
&nbsp;&nbsp; &nbsp;Rotational symmetry
3D
&nbsp;&nbsp; Cube and&nbsp;Tetrahedron
&nbsp;&nbsp; &nbsp; &nbsp;Planes of reflection
&nbsp;&nbsp; &nbsp; &nbsp;Axes of rotational symmetry
Nets

sinx=(1/2)(1+cos2x)

97amb#10

[-cosx]= -[cosx]

graph sketing

should include:
1) turning pt.
2)intercept pt.
3)bounded meeting pt.

ama97#9bII

if r<span style="font-weight: bold;">a</span>=k<span style="font-weight: bold;">a </span>then r=k

ama97#13bI

always focus on the ans question's require

@1st: i used RBnAR as vars, we can concluded that i could find the time only, n the calculation pushed me into trouble.